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If in the hydrogen atom P.E. At oo is c...

If in the hydrogen atom P.E. At `oo` is chosen to be 13.6 eV then the ratio of T.E. to K.E.. For `1^(st)` orbit of H-atom is

A

0

B

2

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
`T.E=-13.6-13.6=0`
`K.E.=13.6+13.6=27.2`
`(TE)/(KE)=0`
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