In a hydrogen atom , in transition of electron a photon of energy 2.55 eV is emitted , then the change in wavelenght of the eletron is

Options

A. `3.32Å`
B. `6.64Å`
C. `9.97Å`
D. None of these

Answer

B

Explanation

`2pir_(n)=nlambda`
`4 to 2`
`lambda_(4)=(2pir_(4))/(4)" "lambda_(2)=(2pir_(2))/(2)`
`lambda_(4)lambda_(2P)=2pi[(0.529(4)^(2))/(1xx4)-(0.529(2)^(2))/(2)]`
=`2pi(0.529)(2)`
`=4pir_(1)`=`6.64 Å`