An unknown particle having double charge as proton itself moves with wavelenght lambda, if it is accelerated from rest through a potential difference of`(V)/(8)`voltus. While proton itself moves with same wavelenght lambda when accelerated from rest thought a potential difference 'V' volts. The particls is

Options

A. `He^(+)`
B. `Li^(2)ion`
C. `He^(2+)`
D. `Be^(2+)`

Answer

C

Explanation

`(lambda)=(h)/sqrt(2mxxexxV)`
`(lambda)=(h)/sqrt(2xxm'xx2exx(V)/(8))`
`mxx2exx(V)/(8)=mxxexxv`
`m'=4m`