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A compound of vanadium has a magnetic ...

A compound of vanadium has a magnetic moment of `1.73BM`. Work out the electronic configuration of vanadium in the compound

A

`[Ar]3d^(1)`

B

`[Ar]3d^(2)`

C

`[Ar]3d^(3)`

D

`[Ar]3d^(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
`sqrt(n(n+2))=1.73`
`n(n+2)=3`
`n=1`
So vandium has 1 unparied electron and its configuration is`[A]3d^(1)`.
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