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The wave function for 1s orbital of hydr...

The wave function for 1s orbital of hydrogen atom is given by:
`Psi_(1s)=(pi)/sqrt2e^(-r//a_(0))`
Where, `a_(0)`= Radius of first Bohar orbit
r= Distance from the nucleus (Probability of finding the ekectron varies with respect to it)
What will be the ratio of probability of finding rhe electron at the nucleus to first Bohr's orbit `a_(0)`?

A

e

B

`e^(2)`

C

`1//e^(2)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
D
For 1 s orbital , porabability of finding thr electron at the nucleus is zero.
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