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The given diagram shows point P(1),P(2)...

The given diagram shows point `P_(1),P_(2)P_(3)&P_(4)` in 1s orbital.

The correct oreder of increasing radial probability at these point are

A

`P_(1)=P_(2)=P_(4)gtP_(3)`

B

`P_(1)=P_(3)ltP_(2)=P_(4)`

C

`P_(1)=P_(3)gtP_(2)=P_(4)`

D

`P_(1)=P_(2)=P_(4)ltP_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Psi^(2)(r)` 1 s orbital do not depend upon angular part ,`therefore p_(1)=p_(3)`
and decrease with increase in distance from the nucleus , therefore `P_(2)ltP_(3)`
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