In sample of hydrogen atoms in ground state, electron make transition from ground state to particular
excited state, where path length is four times of debroglie wavelenght . Electrons make back transition to
the ground state prouducing all possible photons.

Options

A. Wavelenght of photon used for this transition is 121.5 nm
B. Final excitd state of `Li^(+2)` is 6
C. kinetic energy of electron in intaial excited state of `Li^(+2)` is 13.6 eV
D. All are correct

Answer

D

Explanation

`3^(rd)` highest energetic photons `rArr(13.6-3.4)eV=10.2 eV`, transition is `2 to 1`
`lambda=(hc)/(E)=(1240)/(10.2)nm=121.5nm`
For H atoms =gor `Li^(+)`ion
`13.6xx1[1-(1)/(2^(2))]=13.6xx9[(1)/(3^(2))-(1)/(6^(2))]`
`therefore` for `Li^(+)`ion transition is `3 to 6`
Initial excited state=3
Final excited state =6
K.E. of electron in intial excited state of `Li^(+2)`=`13.6xx(3^(3))/(3^(3))`=`13.6 eV`.