Home
Class 11
CHEMISTRY
Statement -I : When projected to words t...

Statement -I : When projected to words towards as atoms having heavy nucleus , most of the `alpha` particle will pass
through it without appereciable decviation. ltbr. Statement -II : All the positive charge of atom is located in a small dense located at center.

A

If both Statement -I & Statement -II are True & the Statement -II is a correct explanation of the Statement
I.

B

If both Statement -I & Statement -II are True but the Statement -II is not a correct explanation of the
Statement- I.

C

If Statement -I is True but the Statement -II is False.

D

If Statement -I is True but the Statement -II is True .

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    BANSAL|Exercise MULTIPLE CORRECT CHOICE TYPE|19 Videos

  • ATOMIC STRUCTURE

    BANSAL|Exercise MATCH THE COLUMN|10 Videos

  • ATOMIC STRUCTURE

    BANSAL|Exercise Exercise.2|21 Videos

  • GENERAL ORGANIC CHEMISTRY

    BANSAL|Exercise Exercise 3|9 Videos

Similar Questions

Explore conceptually related problems

Statement -1 : Large angle scattering of alpha particles led to the discovery of atomic nucleus. Statement -2 : Entire positive charge of atom is concentrated in the central core.

Given below are two statements : Statement I : Most of the mass of the atom and all its positive charge are concentrated in a tiny nucleus and the electrons revolve around it, is Rutherford’s model. Statement II : An atom is a spherical cloud of positive charges with electrons embedded in it, is a special case of Rutherford’s model. In the light of the above statements, choose the most appropriate from the options given below.

Assertion (A) : In Rutherford's experiment, alpha particles from a radium source were allowed to fall on a 10^(-4)mm thick gold foil. Most of the particles passed straight through the foil. Reason (R) : The entire positive charge and nearly whole of the mass of an atom is concentrated in the nucleus.

Statement-I : In Rutherford's gold foil experiment, very few alpha -particles are deflected back. Because Statement-II : Nucleus present inside the atom is heavy.

(a) What observations in scartterting experiment led Rutherford to make the following conclusions? (i) The most of the space in an atom is empty. (ii) The whole of the mass of the atom is present in the centre of the nucleus. (iii) Nucleus has positive charge. (b) What is the value of orbital angular momentum for an electron in 2s orbital ? (c ) How many electrons in an atom may have n = 4 and m_s = + 1//2 ? (d) What physical meaning is attributed to the square of the absolute value of wave function Psi^2 ?

Rutherford model: The approximate size of the nucleus can be calculated by using energy conservation theorem in Rutherford's alpha -scattering experiment. If an alpha -particle is projected from infinity with speed v towards the nucleus having Z protons, then the alpha -particle which is reflected back or which is deflected by 180^@ must have approached closest to the nucleus .It can be approximated that alpha particle collides with the nucleus and gets back. Now if we apply the energy conservation equation at initial point and collision point then: (P.E.)_i= 0 , since P.E. of two charge system separated by infinite distance is zero. Finally the particle stops and then starts coming back. 1/2m_alpha v_alpha^2+0=0+(Kq_1q_2)/Rimplies 1/2m_alphav_alpha^2=K(2exxZe)/R implies R=(4KZe^2)/(m_alphav_alpha^2) Thus the radius of nucleus can be calculated using above equation. The nucleus is so small a particle that we can't define a sharp boundary for it An alpha -particle with initial speed v_0 is projected from infinity and it approaches up to r_0 distance from a nuclie. Then, the initial speed of alpha -particle, which approaches upto 2r_0 distance from the nucleus is :

Statement I: In free space a uniform spherical planet of mass M has a smooth narrow tunnel along its diameter. This planet and another superdense small particle of mass M start approaching towards each other from rest under action of their gravitational forces. When the particle passes through the centre of the planet, sum of kinetic energies of both the bodies is maximum. Statement II: When the resultant of all forces acting on a particle or a particle like object (initially at rest) is constant in direction, the kinetic energy of the particle keeps on increasing.