The velocity of electron in a certain bohr orbit of hydrogen bears the ratio `1 : 275` to the velocity of light
a. What is the quantum number (n) of orbit?
b. Calculate the wave number of radiation emitted when the electron jumps from `(n + 1)` state to the ground state.`(R) = 1.0987 xx 10^(5) cm^(-1)`

Answer

`2;9.75xx10^(4)cm^(-1)`

Explanation

`V=V_(0).(1)/(n)`
`n=(V_(0))/(V)=(2.186xx10^(6)xx275)/(3xx10^(8)xx1)=2`
`barV =R[(1)/(12)-(1)/(2+1)^(2)]=(8)/(9)R`
`barV=9.75xx10^(4) cm^(-1)`