In Wurtz reaction if we take `CH_(3)Cl &C_(2)H_(5)Cl` then product will be

Options

A. propane+ethane
B. propane
C. propane+Ethane+Butane+Ethene
D. Propane+Butane

Answer

To solve the problem regarding the products formed in the Wurtz reaction when methyl chloride (CH₃Cl) and ethyl chloride (C₂H₅Cl) are reacted, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Wurtz Reaction**:
The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal, typically in dry ether. The general reaction can be represented as:
\[ 2 R-X + 2 Na \rightarrow R-R + 2 NaX \]
where R is the alkyl group and X is the halogen (in this case, Cl).

2. **Identifying the Reactants**:
We have two alkyl halides:
- Methyl chloride: CH₃Cl
- Ethyl chloride: C₂H₅Cl

3. **Reactions with Sodium**:
- For CH₃Cl:
- The reaction with sodium leads to the formation of a methyl radical (CH₃•) and sodium chloride (NaCl).
- For C₂H₅Cl:
- The reaction with sodium leads to the formation of an ethyl radical (C₂H₅•) and sodium chloride (NaCl).

4. **Possible Radical Couplings**:
The formed radicals can couple in several ways:
- **Coupling of two methyl radicals**:
\[ CH₃• + CH₃• \rightarrow C₂H₆ \quad (Ethane) \]
- **Coupling of two ethyl radicals**:
\[ C₂H₅• + C₂H₅• \rightarrow C₄H₁₀ \quad (Butane) \]
- **Coupling of one methyl radical and one ethyl radical**:
\[ CH₃• + C₂H₅• \rightarrow C₃H₈ \quad (Propane) \]

5. **Formation of Alkenes**:
- There is also a minor possibility of forming alkenes from the radicals. For example, the combination of radicals can lead to the formation of ethene (C₂H₄) under certain conditions.

6. **Summary of Products**:
From the above reactions, we can summarize the possible products:
- Ethane (C₂H₆)
- Butane (C₄H₁₀)
- Propane (C₃H₈)
- Ethene (C₂H₄)

### Final Answer:
The products formed in the Wurtz reaction of methyl chloride and ethyl chloride are:
- Ethane (C₂H₆)
- Butane (C₄H₁₀)
- Propane (C₃H₈)
- Ethene (C₂H₄)