Polonium crystallises in a primitive cubic structure. The radius of polonium atom and the density of polonium are 1.68Å and `9.27g*cm^(-3)` respectively. If the atomic mass of polonium is `210g*mol^(-1)`, then find the value of Avogadro's number.

Explanation

We know, `rho=(ZxxM)/(Nxxa^(3))`
Given: `rho=9.27g*cm^(-3)andM=210g*mol^(-1)`
For a primitive cubic unit cell, Z = 1 and a = 2r
`therefore" "`Edge length (a) of the unit cell = `2xx1.68Å=3.36Å`
`therefore" "N=(ZxxM)/(rhoxxa^(3))=(1xx210)/(9.27xx(3.36xx10^(-8))^(3))=5.972xx10^(23)`
`therefore" "`The value of Avogadro's number = `5.972xx10^(23)`