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2 volumes of O(3) produce 3 volumes of O...

2 volumes of `O_(3)` produce 3 volumes of `O_(2)` on complete decomposition. 40 mL of a mixture of `O_(3) and O_(2)` is heated at first and then brought back to the previous temperature and pressure. The volume of the gaseous mixture is now found to be 42 mL. find the percentage composition of `O_(3)` in the gas mixture by volume. the volume of all gases are measured under the same conditions of temperature and pressure.

Text Solution

Verified by Experts

Let, the volume of `O_(3)` present in the mentioned gas mixture is x mL. volume of `O_(2)` in the gas mixture=(40-x) mL.
Now, the decomposition of `O_(3)` can be represented as,
`{:(2O_(3),to,3O_(2)),(2" volume",,"3 volume"),(2mL,,3mL),(1mL,,"3/2 mL"):}`
Hence, x mL of `O_(3)` yileds (3/2)x mL of `O_(2)`.
So, the total volume of `O_(2)=(40-x)+(3)/(2)x=(40+(x)/(2))mL`
According to the questions, `O_(3)` is completely decomposed.
So, `40+(x)/(2)=42" or,x=4`
`therefore`Amount of `O_(3)` in the initial mixture`=(4xx100)/(40)=10%`
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