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Calculate the volume of 3.6g of water va...

Calculate the volume of 3.6g of water vapour at 273K temperature and 1 atm pressure.

Text Solution

Verified by Experts

Molecular mass water vapour `(H_(2)O)=18`
`therefore`No. of gram-molecule in 3.6g water vapour`=3.6//18=0.2`
At STP (273K, 1atm), volume of 1 gra-molecule of water vapour=22.4 L
`therefore` At STP, volume of 0.2 gram-molecle of water vapour
=`0.2xx22.4=4.48L`.
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