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If the density of water at 273 K be 1.8g...

If the density of water at 273 K be `1.8g*cm^(-3)`, calculate its molar volume at that temperature.

Text Solution

Verified by Experts

Density of water at 273K=`1.0g*cm^(-3)`
Gra-molecular mass of water=18g
Hence, at 273K the molar volume of water
`=("gram-molecular mass")/("density")=(18g)/(1.0g*cm^(-3))=18cm^(3)`.
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