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Find the number of electrons inn a drop ...

Find the number of electrons inn a drop sulphuric acid weighing `4.9xx10^(-3)`mg [assume it to be cent percent pure].

Text Solution

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`4.9xx10^(-3)mg=4.9xx10^(-6)g`
Molecular mass of `H_(2)SO_(4)=98`
`therefore`Its gram-molecular mass=98g
Number of molecules in 98g of `H_(2)SO_(4)=6.022xx10^(23)`
So, number of molecules in `4.9xx10^(-6)`g of `H_(2)SO_(4)`
`=(6.022xx10^(23)xx4.9xx10^(-6))/(98)=3.011xx10^(16)`
Atomic numbers of H, S and O are 1, 16 and 8 respectively. so, the number of electrons in them are 1, 16 and 8.
`therefore`Total number of electrons present in 1 molecule of `H_(2)SO_(4)=(2xx1+1xx16+4xx8)=50`
`therefore3.011xx10^(16)` number of `H_(2)SO_(4)` molecules contain
`=3.011xx10^(16)xx50=1.5055xx10^(18)` electrons.
Thus, `4.9xx10^(-3)mg` of `H_(2)SO_(4)` have `1.5055xx10^(18)` number of electrons.
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