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Find the number of neutrons present in 5...

Find the number of neutrons present in `5xx10^(-4)` mol of `""^(14)C` isotope.

Text Solution

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Atomic numbe rof carbon=6
`therefore`Number of neutrons in one `""^(14)C` atom`=14-6=8`.
Now, in 1 mol of `""^(14)C`, the number off atoms`=6.022xx10^(23)`
`therefore` In `5xx10^(-4)` mol of `""^(14)C`, the number of atoms
`=(6.022xx10^(23)xx5xx10^(-4))=3.011xx10^(20)`
Again, one `""^(14)C` atom contains 8 neutrons
`therefore 3.011xx10^(20)` number of atoms of `""^(14)C` contain.
`=(8xx3.011xx10^(20))=2.4088xx10^(21)` neutrons.
Number of neutrons in `5xx10^(-4)` mol of `""^(14)C=2.4088xx10^(21)`.
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