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Under the same conditions of temperature...

Under the same conditions of temperature and pressure, a gaseous hydrocarbon contains hydrogen which is twice of its volume. If the vapour density of that hydrocarbon is 14, then what will be its molecular formula?

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According to problem, at the same conditions of temperature and pressure, 1 volume of gaseous hydrocarbon contains 2 volumes of hydrogen.
`therefore`n molecules of gaseous hydrocarbon contain 2n molecules of hydrogen.
or, 1 molecule of gases hydrocarbon contain 2 molecules of hydrogen=4 atoms of hydrogen. (according to avogadro's hypothesis)
`therefore`Molecular formula of hydrocarbon is `C_(x)H_(4)` [where x stands for number of C-atoms]
`therefore`Molecular mass of `C_(x)H_(4)=12xx x+4` [`because` atomic mass of C=12,H=1]
Again, vapour density of the hydrocarbon=14
so, molecular formula of the hydrocarbon`=2xx14=28`
`thereforeC_(x)H_(4)=14xx2`
Therefore, `12x+4=28 or, x=2`
`therefore`Molecular formula of hydrocarbon is `C_(2)H_(4)`.
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