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For complete combusion, 24g of a solid e...

For complete combusion, 24g of a solid element requires 44.8L of `O_(2)` at STP. The gaseous oxide produces in combusion occupies a volume off 44.8 L at STP. What is the molecular mass of the produced gaseous oxide?

Text Solution

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Molar volume of any gas at STP=22.4L
`therefore22.4L` of `O_(2)` at STP=1 gram-molecule of `O_(2)=32g" "O_(2)`
`therefore`Mass of 44.8 L of `O_(2)` at STP=`(32)/(22.4)xx44.8=64g" "O_(2)`.
Now, 24g of a solid element reacts completely with 64g of `O_(2)` to produce a gaseous oxide.
In this case, the total mass of the reactants=(24+64)=88g.
no according to the law of constant proportion (in this case an oxide is only formed) or the law of conservation of mass, the total mass of the product will be 88g.
`therefore`Mass of 44.8L of the gaseous oxide formed at STP=88g
`therefore` Mass of 22.4 L of the gaseous oxide at STP=`(88)/(2)=44g`.
Hence, the gram-molecular mass of the gaseous oxide formed=44g
`therefore` The molecular mass of the gaseous oxide formed=44.
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