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The equivalent mass of a metal is 11.6. ...

The equivalent mass of a metal is 11.6. when 0.177g of that metal is allowed to react completely with dilute HCl, what will be the volume of `H_(2)` gas liberated at `12^(@)C` and 766mm Hg pressure?

Text Solution

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The equivalent mass of the metal is 11.6
`therefore`11.6g metal displaces 11200 mL of `H_(2)` at STP
0.177 g metal displaces `(11200xx0.177)/(11.6)=170.89mL` of `H_(2)`
Let volume be V at `12^(@)C and 760mm` Hg pressure
Let volume be V at `12^(@)C` and 760 mm Hg pressure
`therefore (Vxx766)/((12+273))=(170.89xx760)/(273)`
or, `V=(170.89xx760)/(273)xx(285)/(766)=177.0mL`
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