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A metallic oxide contains 53% metal. The...

A metallic oxide contains 53% metal. The vapour density of the chloride of the metal is 66. find the atomic weight of the metal.

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The metallic oxide contains 53% metal.
`therefore`The metallic oxide contains (100-53)=47% oxygen.
Hence equivalent weight (E) of the metal
`=("mass of the metal")/("mass of oxygen combined")xx8=(53xx8)/(47)=9.02`
As given, vapour density of the metallic chloride=66
`therefore`Molecular weight of the chloride=`2xx66=132`
[`becauseM=2xxD`]
Let, the molecular formula of the metallic chloride be `MC l_(V)` [where, V=valency of the metal]
`therefore` Molecular weight of `MC l_(V)=A+35.5V`
[where A=atomic weight of the metal]
We know, `A=ExxV" "therefore A=9.02xxV`
Hence, `9.02xxV+35.5xxV=132 or, V=(132)/(44.52)~~3`
So, atomic weight of the metal`=ExxV=9.02xx3=27.06`.
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