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In the following reaction, determine the...

In the following reaction, determine the equivalent weight of `H_(3)PO_(4)`.
`Ca(OH)_(2)+H_(3)PO_(4) to CaHPO_(4)+2H_(2)O[Ca=40,P=31]`

Text Solution

Verified by Experts

In this acid-base neutralisation reaction, 2 hydrogenn atoms of `H_(3)PO_(4)` are replaced by 1 atom of calcium.
`therefore` equivalent weight of `H_(3)PO_(4)`
`=("molecular mass of "H_(3)PO_(4))/("number of displaced hydrogen atoms")`
`=(3xx1.008+31+4xx16)/(2)=49.012`
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