3g of hydrated caclium chloride yields 1.52 g of the anhydrous salt on heating. What is the percentage of water present in the hydrated salt? Find the quantity of water associated per mole of the anhydrous salt.

Explanation

Amount of water present in 3g of hydrated calcium chloride=(3-1.52)=1.48g
`therefore` Percentage of water is hydrated salt`=(1.48)/(3)xx100=49.33`
Gram-formula mass of anhy. `CaCl_(2)=(40+2xx35.5)=111g`
Quantity of water associated with 1.2g anhydrous salt=1.48g
`therefore`Quantity of water associated with 111g of 1 mol of the anhydrous salt`=(1.48xx111)/(1.52)=108.07g`
Therefore, the quantity of water associated with 1 mol of anhydrous `CaCl_(2)` is 108.07g.