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Give the percentages of ammonium and sul...

Give the percentages of ammonium and sulphate radicals in Mohr salt `[(NH_(4))_(2)SO_(4)*FeSO_(4)*6H_(2)O]`.

Text Solution

Verified by Experts

Molecular mass of mohr satl
`=(2xx18)+96+56+96+(6xx18)=392`
In each mole of Mohr salt, amount of ammonium `(NH_(4)^(o+))`
radical=`2xx18=36g` and amount of sulphate `(SO_(4)^(2-))` radical `=2xx96=192` g
`therefore` Percentage of ammonium `(NH_(4)^(o+))` radical in Mohr salt `=(36xx100)/(392)=9.18`
Percentage of sulphate `(SO_(4)^(2-))` radical in Mohr salt
`=(192xx100)/(392)=48.98`
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