In three moles of ethane `(C_(2)H_(6))` calculate the following: (1) Number of moles of carbon atoms.
(2) Number of moles of hydrogen aton. (3) Number of molecules of ethane.

Explanation

(1) Number of moles of C-atoms present in 1 mol off ethane `(C_(2)H_(6))=2`
`therefore`Number of moles off C-atoms present in 3 mol of ethane `(C_(2)H_(6))=(2xx3)=6`
(2) Number of moles of H-atoms present in 1 mol of ethane `(C_(2)H_(6))=6`
`therefore` Number of moles of H-atoms present in 3 mol of ethane `(C_(2)H_(6))=(3xx6)=18`
(3) 1 mol ethane `-=6.022xx10^(23)` no. of ethane molecules
`therefore` 3 mol ethane`-=3xx6.022xx10^(23)=1.8066xx10^(24)` no. of ethane molecules.