What is the concentration of sugar `(C_(12)H_(22)O_(11))` in `mol*L^(-1)` if its 20g are dissolved in enough water to make a final volume up to 2L?

Explanation

Molecular mass of sugar`(C_(12)H_(22)O_(11))`
`=(12xx12)+(22xx1.008)+(11xx16.00)=342`
Molarity`=("mass of the solute (in g)")/("gram-molecular mass of the solute"xx"volume of the solution (L)")`
or, molarity of the solution, `(M)=(20)/(342xx2)=0.0293`
Concentration=0.0293`mol*L^(-1)` or 0.293 (M).