The reactant which is entirely consumed in any reaction is known as the limiting reagent. In the reaction, `2A+4B to 3C+4D`, if 5 moles of A react with 6 moles of B, then (1) Which is the limiting reagent?
(2) Calculate the amount of C formed.

Explanation

Reaction: `2A+4B to 3C+4D`
Here, 2 moles of A reacts with 4 moles of B.
Therefore, 5 moles of A reacts with `=(4)/(2)xx5=10` moles of B.
But, we have 6 moles of B participating in the reaction.
(2) It meanns B is the limiting reagent.
(2) 4 moles of B produce 3 moles of C.
Hence, 6 moles of B gives `(3//4)xx6=9//2=4.5` moles of C.