The equivalent weight of `K_(2)Cr_(2)O_(7)` in acidic medium is expressed in terms of its molecular weight (M) as-

Options

A. `M/3`
B. `M/4`
C. `M/6`
D. `M/7`

Answer

C

Explanation

`Cr_(2)O_(7)^(2-)+14H^(+)+6e to 2Cr^(3+)+7H_(2)O`
`therefore`Equivalent weight of `K_(2)Cr_(2)O_(7)`
`=("molecular mass of "K_(2)Cr_(2)O_(7))/("no. of electrons gained by one ion")=(M)/(6)`