Number of hydrogen ions present in 10 millionth parrt of 1.33 `cm^(3)` of pure water at `25^(@)C` is-

Options

A. 6.023 million
B. 60 million
C. 8.01 million
D. 80.23 million

Answer

C

Explanation

10 million`=10^(7)`
so, 10 million th part of `1.33cm^(3)=1.33xx10^(-7)mL`
Now, `[H^(+)]=10^(-7)mol*L^(-1)`
`therefore`1000 mL contains `10^(-7)` mol `H^(+)`
`therefore` 1mL contains `(10^(-7))/(1000)` mol `H^(+)`
`therefore 1.33xx10^(-7)mL` contains `1.33xx10^(-17)mol`
so, no. of `H^(+)` ions`=1.33xx10^(-17)xxN_(A)=8.01` million.