In a flask, the weight ratio of `CH_(4)(g) and SO_(2)(g)` at 298K and 1 bar is 1:2. the ratio of the number of molecules of `SO_(2)(g) and CH_(4)(g)` is-

Options

A. `1:4`
B. `4:1`
C. `1:2`
D. `1:1`

Answer

C

Explanation

`W_(CH_(4)):W_(SO_(2))=1:2`
No. of moles `n=(W)/(M)`
`therefore (n_(SO_(2)))/(n_(CH_(4)))=(W_(SO_(2)))/(M_(SO_(2)))xx(M_(CH_(4)))/(W_(CH_(4)))=(2)/(64)xx(16)/(1)=(1)/(2)`
Ratio of molecules of `SO_(2) and CH_(4)=(2)/(64)xx(16)/(1)=(1)/(2)`.
`=1:2`.