What will be the normality of the salt solution obtained by neutralising x mL y(N) HCl with ymL x(N) NaOH, and finally addition (x+y) mL distilled water-

Options

A. `(2(x+y))/(xy)N`
B. `(xy)/(2(x+y))`
C. `((2xy)/(x+y))`
D. `((x+y)/(xy))N`

Answer

B

Explanation

`{:(,HCl,+,NaOH,to,NaCl,+,H_(2)O),("mequiv. added:",xy,,xy,,0,,0),("mequi. left:",0,,0,,xy,,xy):}`
Normality of the NaCl solution
`=("milliequivalent of NaCl")/("total volume of the solution (mL)")`
`=(xy)/((x+y)+(x+y))=(xy)/(2(x+y))`