A metal M (specific heat=0.16) forms a metal chloride with `~~65%` chlorine present in it. The formula of the metal chloride will be-

Options

A. `MCl`
B. `MCl_(2)`
C. `MCl_(3)`
D. `MCl_(4)`

Answer

B

Explanation

Approximate atomic mass of the metal
`=(6.4)/("specific heat")=(6.4)/(0.16)=40`
Let, the formula of the salt be `MCl_(x)`
% of metal in the salt`=(x xx35.5)/(40+x xx35.5)xx100`
`therefore 65=(x xx3550)/(40+35.5x) or, x=2` (approx.)
`therefore` Formula of the metal is `MCl_(2)`.