The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1:4. the ratio of number of their gram molecules is -

Options

A. `3:16`
B. `1:4`
C. `7:32`
D. `1:8`

Answer

C

Explanation

Let the mass of `O_(2)=x` and that of `N_(2)=4x`
No. of gram molecules of `O_(2)=(x)/(32)" "[O_(2)=32]`
No. of gram molecules of `N_(2)=(4x)/(28)=(x)/(7)" "[N_(2)=28]`
`therefore`Ratio`=(x)/(32):(x)/(7) or, 7:32`