Which has the maximum number of molecules among the following-

Options

A. 44g `CO_(2)`
B. 48g `O_(3)`
C. 8g `H_(2)`
D. 64g `SO_(2)`

Answer

C

Explanation

No. of molecules in 44g `CO_(2)=((44)/(44))xxN_(A)=N_(A)`
No. of molecules in 48g `O_(3)=((48)/(48))xxN_(A)=N_(A)`
No. of molecules in 64g `SO_(2)=((64)/(64))xxN_(A)=N_(A)`
`therefore ` 8g `H_(2)` has `4N_(A)` molecules while the others have `N_(A)` molefcule each.