Equal masses of `H_(2),O_(2)` and methane have been taken in a container of volume V at temperature `27^(@)C` in identical conditions. The ratio of the volumes of gases `H_(2):O_(2)` methane would be-

Options

A. `8:16:1`
B. `16:8:1`
C. `16:1:2`
D. `8:1:2`

Answer

C

Explanation

According to Avogadro's hyppothesis, ratio of volumes of gases will be equal to the ratio of their no. of moles.
So, no. of moles `=(mass)/("mol. Mass")`
`n_(H_(2))=(w)/(2),n_(O_(2))=(w)/(32),n_(CH_(4))=(w)/(16)`
So, the ratio is `(w)/(2):(w)/(32):(w)/(16) or 16:1:2`.