What is the mass of precipitate formed when 50 mL of 16.9% solution of `AgNO_(3)` is mixed with 50 mL of 5.8% NaCl solution (Ag=107.8, N=14, O=16, Na=23, Cl=35.5)-

Options

A. 28g
B. 3.5g
C. 7g
D. 14g

Answer

C

Explanation

16.9% solution of `AgNO_(3)` means 16.9g `AgNO_(3)` is present in 100 mL solution.
`therefore 8.45" "AgNO_(3)` will be present in 50 mL solution
Similarly, 5.8g NaCl is present in 100 mL solution
`therefore 2.9g" "NaCl` is present in 50 mL solution
`{:(,AgNO_(3),+,NaCl ,to,AgCl,+,NaNO_(3)),("Initially:",(8.45)/(169.8)=0.049,,(2.9)/(58.5)=0.049,,0,,0),("After reaction:",0,,0,,0.049,,0.049):}`
`therefore`Mass of AgCl precipitated `=0.049xx143.5=7g`