Home
Class 11
CHEMISTRY
5.3g of M(2)CO(3) is dissolved in 150 mL...

5.3g of `M_(2)CO_(3)` is dissolved in 150 mL of 1(N) HCl. Unused acid required 100 mL of 0.5(N) NaOH. Hence equivalent weight of M is-

A

23

B

12

C

24

D

13

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise EXERCISE (VERY SHORT TYPE QUESTIONS)|25 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise EXERCISE (FILL IN THE BLANKS)|24 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK|46 Videos
  • s-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|16 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

4.08g of a mixture of BaO and unknown carbonate (MCO_(3)) was heated strongly. The residue weghing 3.64g was dissolved in 100 mL of 1(N) HCl. The excess acid required 16 mL of 2.5(N) NaOH solution for complete neutralisation. Identify the metal.

2g of metal carbonate is neutralised completely by 100 mL of 0.1 (N) HCl. The equivalent weight of metal carbon ate is-

0.126g of an acid is needed to completely neutralise 20 mL 0.1 N NaOH solution. The equivalent weight of the acid is-

A sample of 3.95g of 60% pure chalk (impurities in the chalk are insoluble in HCl), is dissolved in 250 mL of 0.2(M) HCl. What volume (cm^(3)) of 0.01 (N) NaOH is required to neutralise the excess acid?

10 g of a sample of Ca(OH)_2 is dissolved in 10 mL of 0.5 N HCL solution . The excess of HCl was titrated with 0.2 N NaOH. The volume of NaOH used was 10 cc. Calculate the percentage of Ca(OH)_2 in the sample.

The pH of solution obtained by mixing 10 ml of 10^-1 N HCl and 10 ml of 10^-1 N NaOH is

0.257 g of an organic substance was Kjeldahlised and ammonia evolved was absorbed in 50 mL of N/10 HCl which required 23.2 ml of N/10 NaOH for neutralization. Determine the percentage of nitrogen in the compound.

0.05g of an organic compound was treated according to Kjedahl's method. Ammonia evoled was absorbed in 50ml of 0.05 (M) H_(2)S)_(4) . The residual acid required 60 ml 0.5 (M) solution of NaOH for neutralisation. Find the percentage composition of N in the compound.

0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 m! of N/20KMnO_4 for complete oxidation. The % of oxalate ion in salt is

0.35 g of an organic substance was Kjeldahlised and the ammonia obtained was passed into 100 ml of N/5 H_(2)SO_(4) . The excess acid required 154 ml of N/10 NaOH for neutralisation. Calculate the percentage of nitrogen in the compound.

CHHAYA PUBLICATION-SOME BASIC CONCEPTS OF CHEMISTRY-MCQ HOTSPOT (SINGLE CORRECT TYPE)
  1. 10g of pyrolusite on reaction with conc. HCl liberated 0.1 equivalent ...

    Text Solution

    |

  2. 100 mL of 30% (m/v) NaOH solution is mixed with 100 mL of 90% (m/v) N...

    Text Solution

    |

  3. 5.3g of M(2)CO(3) is dissolved in 150 mL of 1(N) HCl. Unused acid requ...

    Text Solution

    |

  4. Methane was burnt in an incorrectly adjusted burner. The methane was c...

    Text Solution

    |

  5. The equivalent weight of MnSO(4) is half of its molecular mass when it...

    Text Solution

    |

  6. Mass percent of carbon in carbon dioxide is-

    Text Solution

    |

  7. If the concentration of glucose in blood is 0.9 g*L^(-1), then its mol...

    Text Solution

    |

  8. In an experiment, 4g M(2)O(x) oxide was reduced to 2.8g of the metal. ...

    Text Solution

    |

  9. Specific volume of a cylinderical virus particle is 6.02xx10^(-2)"cc"*...

    Text Solution

    |

  10. 10 mL of CS(2) (Specific gravity 2.63) is burnt in oxygen. Volume of t...

    Text Solution

    |

  11. An element X has the following isotopic composition- ""^(200)X:90%,""^...

    Text Solution

    |

  12. At room temperature the no of molecules present in 1 drop of water (vo...

    Text Solution

    |

  13. if a signature contains 1mg of C-atom then number of C-atom in the sig...

    Text Solution

    |

  14. No. of valence electron present in 4.2g nitride ion is-

    Text Solution

    |

  15. An element forms four compounds A, B, C & D. ratio of equivalent weigh...

    Text Solution

    |

  16. In which of the following compounds M has the highest equivalent weigh...

    Text Solution

    |

  17. Atomic mass of two compounds A and B is 30 and 60 respectively. Iff Xg...

    Text Solution

    |

  18. Density (in g*mL^(-1)) of a 3.60(M) H(2)SO(4) solution that is 29% H(2...

    Text Solution

    |

  19. Polyethylene can be produced from CaC(2) according to the following se...

    Text Solution

    |

  20. The weight of one molecular of a compound C(60)H(122) is-

    Text Solution

    |