Home
Class 11
CHEMISTRY
if a signature contains 1mg of C-atom th...

if a signature contains 1mg of C-atom then number of C-atom in the signature is-

A

`6.02xx10^(20)`

B

`0.502xx10^(20)`

C

`5.02xx10^(23)`

D

`5.02xx10^(20)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise EXERCISE (VERY SHORT TYPE QUESTIONS)|25 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise EXERCISE (FILL IN THE BLANKS)|24 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK|46 Videos
  • s-BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|16 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

The minimum number of C atoms present in ketone is-

2.0 g of oxygen contains number of atoms same as in

The system that contains the maximum number of atoms is

Find the oxidation number of each C atom in C_3O_2

Calculate the number of H & O atoms in 90 gm water at 4^@C .

What is the number of helium atoms in 1 mole He?

Suppose we consider a large number of containers each containing initially 10000 atoms of radioactive material with a half-life of 1 year. After 1 year, (A) All containers will have 5000 atoms (B) All the containers will contain the same number of atoms but that number will only be approximately 5000. (C) The containers will in general have different numbers of the atoms but their average will be close to 5000. (D) None of the containers can have more than 5000 atoms.

Calculate the mass of diamond that will contain the same number of C-atoms as that in 0.1g of graphite.

Which of the following contain(s) the greatest number of atoms ?

Which of the following contains greatest number of oxygen atoms ?

CHHAYA PUBLICATION-SOME BASIC CONCEPTS OF CHEMISTRY-MCQ HOTSPOT (SINGLE CORRECT TYPE)
  1. An element X has the following isotopic composition- ""^(200)X:90%,""^...

    Text Solution

    |

  2. At room temperature the no of molecules present in 1 drop of water (vo...

    Text Solution

    |

  3. if a signature contains 1mg of C-atom then number of C-atom in the sig...

    Text Solution

    |

  4. No. of valence electron present in 4.2g nitride ion is-

    Text Solution

    |

  5. An element forms four compounds A, B, C & D. ratio of equivalent weigh...

    Text Solution

    |

  6. In which of the following compounds M has the highest equivalent weigh...

    Text Solution

    |

  7. Atomic mass of two compounds A and B is 30 and 60 respectively. Iff Xg...

    Text Solution

    |

  8. Density (in g*mL^(-1)) of a 3.60(M) H(2)SO(4) solution that is 29% H(2...

    Text Solution

    |

  9. Polyethylene can be produced from CaC(2) according to the following se...

    Text Solution

    |

  10. The weight of one molecular of a compound C(60)H(122) is-

    Text Solution

    |

  11. A 2.0g mixture of Na(2)CO(3) and NaHCO(3) suffered a loss of 0.12g on ...

    Text Solution

    |

  12. Which of the following does not have same percentage of carbon as in e...

    Text Solution

    |

  13. xL of nitrogen at STP contains 3xx10^(22) molecules. The number of mol...

    Text Solution

    |

  14. A sample of AlF(3) contains 3xx10^(25)F-ions. The number of AlF^(3+) i...

    Text Solution

    |

  15. X and Y are the two elements which form X(2)Y(3) and X(3)Y(4). 0.2 mol...

    Text Solution

    |

  16. Percentage of Se (atomic weight=78.4) in peroxidase anhydrase enzyme i...

    Text Solution

    |

  17. How many mole of magnesium phosphate will contain 0.25 mol of oxygen a...

    Text Solution

    |

  18. Amount of calcium oxide required, when it reacts with 852g of P(4)O(10...

    Text Solution

    |

  19. 25.3g of Na(2)CO(3) is dissolved in enough water to make 250 ml of sol...

    Text Solution

    |

  20. How many moles of lead (II) chloride will be formed from a reaction be...

    Text Solution

    |