Calculate the number of O-atoms in 88g of `CO_(2)`. Also calculate the mass of CO which will contain the same number of O-atoms.

Explanation

88g `CO_(2)=(88)/(44)=2" mol "CO_(2)`
1 mol of `CO_(2)` contains `2xx6.022xx10^(23)` no. of oxygen atoms.
`therefore`2 mol of `CO_(2)` contains `4xx6.022xx10^(23)`
`=2.4088xx10^(24)` number of oxygen atoms.
Number of oxygen atoms in 1 mol `CO=6.022xx10^(23)`
`therefore 2.4088xx10^(24)` number of oxygen atoms present in
`=(2.4088xx10^(24))/(6.022xx10^(23))` mol of CO=4 mol of CO
`=4xx28g" of "CO=112g` of CO.