5g of a metal on ignition inn air forms ...

5g of a metal on ignition inn air forms 9.44g of its oxide. Calculate the equivalent mass of the metal.

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Metal present in 9.44g of its oxide=5g
`therefore`Oxygenn present in 9.44g oxide`=(9.44-5)g=4.44g`
`therefore`Equivalent mass of the metal`=(5xx8)/(4.44)=9`

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