1.256g of ametal contains 0.376g of oxygen. If the specific heat off the metal be 0.124 `cal*""^(@)C^(-1)*g^(-1)`, find the formula of its oxide.

Explanation

Amount of metal present`=(1.256-0.376)g=0.88g`
`therefore`Equivalent mass of the metal`(0.88)/(0.376)xx8=18.72`
Approximate atomic mass of the metal`=(6.4)/(0.124)=51.61`
`therefore` Valency of the metal `=(51.61)/(18.72)=2.75~~3` [nearest whole number]
`therefore`Formula of the metallic oxide is `M_(2)O_(3)`.