Mass of an empty LPG cylinder is 14.8 kg annd when it is filled with n-butan gas, the mass is 29.0 kg annd internal pressure is 2.5 atm. After few days mass of the filled gas cylinder decreases to 23.2kg. Calculate the volume of gas used in `m^(3)` (at `27^(@)C ` & 1 atm).

Explanation

Mass of the used n-butane`=(29.0-3.2)kg=5.8kg`
`therefore`Number of moles of the gas`=(5.8xx1000)/(58)=100`
`therefore` Volume of the gas,
`V=(nRT)/(P)=(100xx0.0821xx(27+273))/(1.0)`
`=2.463L=2.463m^(3)[because 1m^(3)=10^(3)L]`