0.19 g of a improve `H_(2)O_(2)` sample is dissolve din a 20 mL solution. 0.316g of the solution reacts completely with `KMnO_(4)` in presence of `H_(2)SO_(4)`. Find the purity of `H_(2)O_(2)` sample.

Explanation

`underset(2xx158g)(2KMnO_(4))+underset(5xx34g)(5H_(2)O_(2))+u3H_(2)SO_(4) to K_(2)SO_(4)+2MnSO_(4)+5O_(2)+8H_(2)`
`H_(2)O_(2)` required to react completely
`=((5xx34)xx0.316)/(2xx158)g=0.17g`
`therefore`Percentage purity of `H_(2)O_(2)` sample `=(0.17xx100)/(0.19)=89.47`.