A metal M of atomic masss 54.94 has a density of 7.42g/`cm^(3)`. Calculate the volume occupied and the radius of the atom of this metal assuming it to be a sphere.

Explanation

We know, volume of atom `xx`its density
`=("atomic weight.")/("avogadro number")`
Ionic radius of atom=r, its volume`=(4)/(3)pir^(3)`
`(4)/(3)pir^(3)xx7.42=(54.94)/(6.023xx10^(23))" "thereforer=1.432xx10^(-8)cm`
Volume`=(4)/(3)pir^(3)=(4)/(3)pixx(1.432xx10^(-8))^(3)`
`=1.23xx10^(-23)cm^(3)`