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A sample of oxygen contains the isotope,...

A sample of oxygen contains the isotope, `""^(18)O`. How many neutrons are present in 11.2 L of the gas at STP?

Text Solution

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Atomic number of oxygen=8
`therefore`Number of neutrons in an `""^(18)O` isotope=18-8=10
Number of atoms in 22.4 of `""^(18)O` isotope at STP
`=2xx6.022xx10^(23)`
`therefore`Number of neutrons in 22.4 L of `""^(18)O` isotope at STP
`=10xx2xx6.022xx10^(23)" "[because" oxygen molecule is diatomic"]`
`therefore`Number of neutrons in 11.2 L of `""^(18)O` isotope at STP
`=(10xx2xx6.022xx10^(23)xx11.2)/(22.4)`
`=6.022xx10^(24)`
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