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A sample contains two isotopes, ""^(16)O...

A sample contains two isotopes, `""^(16)O and ""^(18)O`. How many protons are present in 11.2 L of the sample at STP. What would be the difference in the no. of protons, if the sample contains only one isotope?

Text Solution

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Each of the atos of `""^(16)O and ""^(18)O` 8 protons (atomic number of oxygen=8)
total number of atoms inn 22.4 L oxygen (`""^(16)O and ""^(18)O`) at STP
`=6.022xx10^(23)xx2" "[because" oxygen molecule is diatomic"]`
Number of protons in 22.4 L oxygen sample at STP `=8xx6.022xx10^(23)xx2`
`therefore`Number of protons in 11.2 L oxygen sample at STP
`=(8xx2xx6.022xx10^(23)xx11.2)/(22.4)`
`=4.8176xx10^(24)`
If the sample contains only one isotopes, then there will be no difference in the number of protons because both `""^(16)O and ""^(18)O` isotopes contain 8 protons in their atoms.
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