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A ray of light of frequency 5000 Å is in...

A ray of light of frequency 5000 Å is incident on a metal surface and thus, absorbs `10^(-7)J` of energy. Calculate the number of photons incident on the metal surface.

Text Solution

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Let the number of photons incident on metal surface=n
`therefore nhv=10^(-7) or, (nhc)/(lamda)=10^(-7)`
or, `(nxx6.626xx10^(-34)xx3xx10^(8))/(5000xx10^(-10))=10^(-7)`
or, `n=(10^(-7)xx5000xx10^(-10))/(6.626xx10^(-34)xx3xx10^(8))=2.51xx10^(11)`
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