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If a light with frequency 2.0xx10^(16)Hz...

If a light with frequency `2.0xx10^(16)Hz` emitted photoelectrons with double the kinetic energy as are emitted by the light of frequency `1.25xx10^(16)Hz` from the same metal surface, calculate the threshold frequency of the metal.

Text Solution

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Kinetic energy of photoelectrons `((1)/(2)mv^(2))=h(v-v_(0))`
Given, `h(2.0xx10^(16)-v_(0))=h(1.25xx10^(16)-v_(0))xx2`
or, `v_(0)=(2.5-2.0)xx10^(16)=0.5xx10^(16)=5xx10^(15)Hz`.
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