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When a radiation of frequency 7.5xx10^(1...

When a radiation of frequency `7.5xx10^(14)Hz` strikes a metal surface, the maximum kinetic enegy attained by the emitted electrons is `1.6xx10^(-19)J`. Calculate the threshold frequency of the metal.

Text Solution

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Kinetic energy of emitted electrons, `((1)/(2)mv^(2))=h(v-v_(0))`
given, `1.6xx10^(-19)=h(v-v_(0))`
or, `(1.6xx10^(-19))/(6.626xx10^(-34))=7.5xx10^(14)-v_(0)`
or, `v_(0)=7.5xx10^(14)-2.41xx10^(14)=5.09xx10^(14)Hz`
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