Home
Class 11
CHEMISTRY
Identify the spectral line having wavele...

Identify the spectral line having wavelength of `4.863xx10^(-5)cm` in the emission spectra of hydrogen.

Text Solution

Verified by Experts

Wave no, `overline(v)=[(1)/(2^(2))-(1)/(n^(2))]` [given, `lamda=4.863xx10^(-5)cm`]
`therefore overline(v)=(1)/(lamda)=(1)/(6.863xx10^(-5))=109678=[(1)/(4)-(1)/(n^(2))]`
`therefore (1)/(n^(2))=(1)/(4)-(1)/(4.863xx10^(-5)xx109678)=0.0625 or, n=4`
The spectral line with wavelength `4.863xx10^(-5)cm` is `H_(beta)`.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|157 Videos
  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise QUESTION ANSWER ZONE FOR BOARD EXAMINATION (VERY SHORT ANSWER TYPE)|28 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

Calculat ethe wave length and frequency associated with the spectral line having longest wave lengthin the Pfund series of hyrogen spectra.

Calculate the wavelength of the spectral line having minimum energy in the Lyman series of hydrogen atom.

Calculate the wavelengths of H_(alpha) and H_(delta) in the emission spectrum of hydrogen. [R=109678 cm^(-1) ].

The ratio of the wavelength of K_(beta) and K_(alpha) spectral lines of hydrogen is

What element has a H like spectrum whose lines have wavelength four times shorter than those of atomic hydrogen?

Calculate the wavelength of the spectral line with n_(2)=3 in Lyman series of hydrogen atom.

When ultraviolet rays of wavelength 620 Å is incident on a hydrogen atom in the ground state, its electron is emitted with a velocity of 1.5 xx10^(6) m *s^(-1) . What is the ionisation energy of hydrogen ? Given , h= 6.625xx10^(-34)J *s , mass of electron = 9.1 xx 10^(-31)kg, c=3xx 10^(8)m*s^(-1) and 1 eV=1.6xx 10^(-19)J .

In a microwave over the electromagnetic waves are generated having wavelength of the order of 1 cm. Find the energy of the microwave photon. (h = 6.33 xx 10^(-34) J.s) .

The radiation emitted when a hydrogen atom goes from a higher energy state to a lower energy state. The wavelength of one line in visible region of atomic spectrum of hydrogen is 6.63xx10^(-7) m. Energy difference between the two state is

With the help of Balmer's relation, show how the wavelengths of the spectral lines of hydrogen can be determined.