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If the energy of first Bohr orbit is -13...

If the energy of first Bohr orbit is -13.58eV, then what will be the energy of the third Bohr orbit?

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Energy of n-th Bohr-orbit of H-atom, `E_(n)=-(2pi^(2)me^(2))/(n^(2)h^(2))`
`therefore`Energy of first Bohr orbit, `E_(1)=-(2pi^(2)me^(4))/(1^(2)xxh^(2))`
`therefore`Energy of third Bohr orbit, `E_(3)=-(2pi^(2)me^(4))/(3^(2)xxh^(2))`
Hence, `(E_(3))/(E_(1))=(2pi^(2)me^(4))/(9xxh^(2))xx(h^(2))/(2pi^(2)me^(4))=(1)/(9)`
`therefore E_(3)=(1)/(9)xxE_(1)=(1)/(9)xx(-13.58)eV=-1.509eV`.
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